抱歉,您的浏览器无法访问本站
本页面需要浏览器支持(启用)JavaScript
了解详情 >

靖待的技术博客

小清新IT旅程 | 为中华之崛起而读书





  C++ Programming(part II), and Object Model.
  侯捷
  笔记


前言

应具备的基础

  • 是上一篇博文“面向对象程序设计”的续集
  • 本文将探讨上文未讨论的主题

目标

  • 在先前培养正规、大器的编程素养上,继续探讨更多技术。
  • 泛型编程(Generic Programming)和面向对象编程(Object-Oriented Programming)虽然分属不同思维,但它们正是C++的技术主线。本文也讨论template(模板)。
  • 深入探索面向对象之继承关系(inheritance)所形成的对象模型(Object Model),包括隐藏于底层的this指针,vptr指针(虚指针),vtbl(虚表),virtual mechanism(虚机制),以及虚函数(virtual functions)造成的polymorphism(多态)效果。

将获得的代码

Test-Cpp.cpp

C++编译器

  • 编译(compile)
  • 连接(link)

conversion function, 转换函数

1
2
3
4
5
6
7
8
9
10
11
12
class Fraction
{
public:
Fraction(int num, int den=1):m_numerator(num), m_denominator(den) { }
operator double() const
{
return (double)(m_numerator / m_denominator)
}
private:
int m_numerator;//分子
int m_denominator;//分母
};

使用:

1
2
Fraction f(3, 5);
double d = 4 + f;//调用operator double()将f转为0.6

non-explicit-one-argument ctor

1
2
3
4
5
6
7
8
9
10
11
12
13
class Fraction
{
public:
Fraction(int num, int den=1):m_numerator(num), m_denominator(den) { }

Fraction operator+(const Fraction& f)
{
return Fraction(......);
}
private:
int m_numerator;
int m_denominator;
};

使用:

1
2
Fraction f(3, 5);
Fraction d2 = f + 4;//调用non-explicit ctor将4转为Fraction(4, 1),然后调用operator+

conversion function vs. non-explicit-one-argument ctor

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
class Fraction
{
public:
Fraction(int num, int den=1):m_numerator(num), m_denominator(den) { }
operator double() const
{
return (double) (m_numerator / m_denominator);
}
Fraction operator+(const Fraction& f)
{
return Fraction(......);
}
private:
int m_numerator;
int m_denominator;
};

使用:

1
2
Fraction f(3, 5);
Fraction d2 = f + 4;//[ERROR]ambiguous 二义

explicit-one-argument ctor

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
class Fraction
{
public:
explicit Fraction(int num, int den=1):m_numerator(num), m_denominator(den) { }
operator double() const
{
return (double) (m_numerator / m_denominator);
}
Fraction operator+(const Fraction& f)
{
return Fraction(......);
}
private:
int m_numerator;
int m_denominator;
};

使用:

1
2
Fraction f(3, 5);
Fraction d2 = f + 4;//[ERROR]conersion from 'double' to 'Fraction' requested

conversion function, 转换函数
proxy

1
2
3
4
5
6
7
8
9
10
11
template<class Alloc>
class vector<bool, Alloc>
{
public:
typedef __bit_reference reference;
protected:
reference operator[] (size_type n)
{
return *(begin() + difference_type(n));
}
...

1
2
3
4
5
6
7
8
struct __bit_reference
{
unsigned int* p;
unsigned int mask;
...
public:
operator bool() const {return !(!(*p & mask)); }
...

pointer-like classes, 关于智能指针

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
template<class T>
class shared_ptr
{
public:
T& operator*() const
{return *px;}

T* operator->() const
{return px;}

shared_ptr(T* p):px(p) { }

private:
T* px;
long* pn;
...
};

使用:

1
2
3
4
5
struct Foo
{
...
void method(void) {......}
};

1
2
3
4
5
shared_ptr<Foo> sp(new Foo);

Foo f(*sp);

sp->method();

相当于
1
px->method();

pointer-like classes, 关于迭代器

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
template<class T, class Ref, class Ptr>
struct __list_iterator
{
typedef __list_iterator<T, Ref, Ptr> self;
typedef Ptr pointer;
typedef Ref reference;
typedef __list_node<T>* link_type;
link_type node;
bool operator==(const self& x) const {return node == x.node; }
bool operator!=(const self& x) const { return node != x.node; }
reference operator*() const { return {*node}.data; }
pointer operator->() const { return &(operator*());}
self& operator++() { node = (link_type)((*node).next); return *this;}
self operator++(int) { self tmp = *this; ++*this; return tmp;}
self& operator--() { node = (link_type)((*node).prev); return *this;}
self operator--(int) { self tmp = *this; --*this; return tmp; }
};

使用:

1
2
3
4
5
6
7
list<Foo>::iterator ite;
...
*ite;//获得一个Foo object
ite->method();
//意思是调用Foo::method()
//相当于(*ite).method();
//相当于(&(*ite))->method();

funciton-like classes, 所谓仿函数

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
template <class T>
struct identity
{
const T&
operator() (const T& x) const { return x; }
};

template <class Pair>
struct select1st
{
const typename Pair::first_type&
operator() (const Pair& x) const
{ return x.first; }
};

template <class Pair>
struct select2nd
{
const typename Pair::second_type&
operator() (const Pair& x) const
{ return x.second; }
};
1
2
3
4
5
6
7
8
9
template <class T1, class T2>
struct pair
{
T1 first;
T2 second;
pair() : first(T1()), second(T2()) {}
pair(const T1& a, const T2& b): first(a), second(b) {}
......
};

标准库中仿仿函数的奇特模样

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
template <class T>
struct identity : public unary_function<T, T>
{
const T&
operator() (const T& x) const { return x; }
};

template <class Pair>
struct select1st : public unary_function<Pair, typename Pair::first_type>
{
const typename Pair::first_type&
operator() (const Pair& x) const
{ return x.first; }
};

template <class Pair>
struct select2nd : public unary_function<Pair, typename Pair::second_type>
{
const typename Pair::second_type&
operator() (const Pair& x) const
{ return x.second; }
};
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
template <class T>
struct plus : public binary_function<T, T, T>
{
T operator()(const T& x, const T& y) const { return x + y; }
};
template <class T>
struct minus : public binary_function<T, T, T>
{
T operator()(const T& x, const T& y) const { return x - y; }
};
template <class T>
struct equal_to : public binary_function<T, T, bool>
{
T operator()(const T& x, const T& y) const { return x == y; }
};
template <class T>
struct plus : public binary_function<T, T, bool>
{
T operator()(const T& x, const T& y) const { return x < y; }
};

标准库中,仿函数所使用的奇特的base classes

1
2
3
4
5
6
7
8
9
10
11
12
13
14
template <class Arg, class Result>
struct unary_function
{
typedef Arg argument_type;
typedef Result result_type;
};

template <class Arg1, class Arg2, class Result>
struct binary_function
{
typedef Arg1 first_argument_type;
typedef Arg2 second_argument_type;
typedef Result result_type;
};

less::result_type->bool

namespace经验谈

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
using namespace std;
//-----------------------------------
#include<iostream>
#include<memory>//share_ptr
namespace jj01
{
void test_member_template()
{ ...... }
}//namespace
//-----------------------------------
#include<iostream>
#include<list>
namespace jj02
{
template<typename T>
using Lst = list<T, allocator<T>>;
void test_template_template_param()
{ ...... }
}//namespace
//-----------------------------------

使用:

1
2
3
int main(int argc, char** argv)
jj01::test_member_template();
jj02::test_template_template();

class template, 类模板

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
template<typename T>
class complex
{
public:
complex(T r = 0, T i = 0)
: re(r), im(i)
{}
complex& operator += (const complex&);
T real () const { return re; }
T imag () const { return im; }
private:
T re, im;

friend complex& __doapl (complex*, const complex&);
};

使用:

1
2
3
4
5
{
complex<double> c1(2.5, 1.5);
complex<int> c2(2, 6);
...
}

function template, 函数模板

1
2
stone r1(2, 3), r2(3, 3), r3;
r3 = min(r1, r2);

编译器会对function template进行实参推导(argument deduction)

1
2
3
4
5
template <class T>
inline const T& min(const T& a, const T& b)
{
return b < a ? b : a;
}

实参推导的结果,T为stone,于是调用stone::operator<
1
2
3
4
5
6
7
8
9
10
11
class stone
{
public:
stone(int w, int h, int we)
: _w(w), _h(h), _weight(we)
{ }
bool operator< (const stone& rhs) const
{ return _weight < rhs._weight; }
private:
int _w, _h, _weight;
};

member template, 成员函数

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
template <class T1, class T2>
struct pair
{
typedef T1 first_type;
typedef T2 second_type;

T1 first;
T2 second;

pair()
: first(T1()), second(T2()) {}
pair(const T1& a, const T2& b)
: first(a), second(b) {}
template <class U1, class U2>
pair(const pair<U1, U2>& p)
: first(p.first), second(p.second) {}
};
1
2
3
4
5
class Base1{};
class Derived1:public Base1{};

class Base2{};
class Derived2:public Base2{};
1
2
pair<Derived1, Derived2>p;
pair<Base1, Base2>p2(p);
1
pair<Base1, Base2>p2(pair<Derived1, Derived2>());
1
2
3
4
5
6
7
8
9
template<typename _Tp>
class shared_ptr:public __shared_ptr<_Tp>
{
...
template<typename _Tp1>
explicit shared_ptr(_Tpl* __p)
:__shared_ptr<_Tp>(__p){}
...
};
1
2
Base1* ptr = new Derived1;//up-cast
shared_ptr<Base1>sptr(new Derived1);//模拟up-cast

specialization, 模板特化

【注】特化反义词:泛化

泛化

1
2
template <class Key>
struct hash{ };

特化

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
template<>
struct hash<char>
{
size_t operator() (char x) const { return x; }
};

template<>
struct hash<int>
{
size_t operator() (int x) const { return x; }
};

template<>
struct hash<long>
{
size_t operator() (long x) const { return x; }
};

使用:

1
cout << hash<long>() (1000);

泛化又叫full specialization,全泛化,对应偏特化。

patial specialization, 模板偏特化——个数的偏

1
2
3
4
5
template<typename T, typename Alloc=...>
class vector
{
...
};

绑定

1
2
3
4
template<typename Alloc=...>
class vector<bool, Alloc>
{
...

patial specialization, 模板偏特化——范围的偏

1
2
3
4
5
template <typename T>
class C
{
...
};

【注】上下的T不是一个T

1
2
3
4
5
template <typename T>
class C<T*>
{
...
};

这样写也可以
1
2
3
4
5
template <typename U>
class C<U*>
{
...
};

使用:
1
2
C<string> obj1;
C<string*> obj2;

template template parameter, 模板模板参数

1
2
3
4
5
6
7
8
9
10
11
template<typename T, 
template <typename T>
class Container
>
class XCls
{
private:
Container<T> c;
public:
......
};
1
2
template<typename T>
using Lst = list<T, allocator<T>>;
1
2
XCls<string, list> mylst1;//错误
XCls<string, Lst> mylst2;
1
2
3
4
5
6
7
8
9
10
11
template<typename T,
template <typename T>
class SmartPtr
>
class XCls
{
private:
SmartPtr<T> sp;
public:
XCls():sp(new T) { }
};
1
2
3
4
XCls<string, shared_ptr> p1;
XCls<string, unique_ptr> p2;//错误
XCls<int, weak_ptr> p3;//错误
XCls<long, auto_ptr> p4;

这不是template template parameter

1
2
3
4
5
6
7
8
9
10
template <class T, class Sequence = deque<T>>
class stack
{
friend bool operator== <> (const stack&, const stack&);
friend bool operator< <> (const stack&, const stack&);

protected:
Sequence c;//底层容器
......
};

使用

1
2
stack<int> s1;
stack<int, list<int>> s2;

关于C++标准库

容器

Sequence containers

array
vector
deque
forward_list
list

Container adaptors

stack
queue
priority_queue

Associative containers

set
multiset
map
multimap

Unordered associative con

unordered_set
unordered_multiset
unordered_map
unordered_multimap

算法

Sorting

sort
stable_sort
partial_sort
partial_sort_copy
is_sorted
is_sorted_until
nth_element

lower_bound
upper_bound
equal_range
binary_search

Merge

merge
inplace_merge
includes
set_union
set_intersection
set_difference
set_symmetric_difference

推书:Algorithms + Data Structures = Programs(Niklaus Wirth)

确认支持C++11: macro __cplusplus
测试:
VS2012

1
2
3
4
5
6
7
8
9
#include"stdafx.h"
#include <iostream>
using namespace std;

int main()
{
cout<<__cplusplus<<endl;
return 0;
}

Dev-C++ 5

1
2
3
4
5
6
#include <iostream>

int main()
{
std::cout<<__cplusplus;
}

如果是199711,则不支持C++11,需修改编译器
如果是201103,则支持C++11

variadic templates(since C++11) 数量不定的模板参数

1
2
3
4
5
6
7
8
9
10
void print()
{
}

template<typename T, typename... Types>
void print(const T& firstArg, const Type&... args)
{
cout<<firstArg<<endl;
print(args...);
}

Inside variadic templates, sizeof…(arg) yields the number of arguments

…就是一个所谓的pack(包)
用于template parameters, 就是template parameters pack(模板参数包)
用于function parameter types, 就是function parameter types pack(函数参数类型包)
用于function parameters, 就是function parameters pack(函数参数包)

使用:

1
print(7.5, "hello", bitset<16>(377), 42);

结果:
1
2
3
4
7.5
hello
0000000101111001
42

auto(since C++11)

过去:

1
2
3
4
list<string> c;
...
list<string>::iterator ite;
ite = find(c.begin(), c.end(), target);

现在:
1
2
3
list<string> c;
...
auto ite = find(c.begin(), c.end(), target);

错误:
1
2
3
4
list<string> c;
...
auto ite;//错误
ite = find(c.begin(), c.end(), target);

ranged-base for(since C++11)

1
2
3
4
for(decl : coll)
{
statement
}
1
2
3
4
for(int i : {2, 3, 5, 7, 9, 13, 17, 19})
{
cout<< i << endl;
}
1
2
3
4
5
6
7
8
9
10
11
vector<double> vec;
...
for(auto elem : vec)//pass by value
{
cout << elem << endl;
}

for(auto& elem : vec)// pass by reference
{
elem *= 3;
}

reference

1
2
3
4
5
6
7
int x=0;
int* p = &x;
int& r = x;//r代表x。现在r,x都是0
int x2 = 5;

r = x2;//r不能重新代表其他物体。现在r,x都是5
int& r2 = r;//现在r2是5(r2代表r:亦相当于代表x)

从内存上看,
从内存上看

注意:

  1. sizeof(r) == sizeof(x)
  2. &x = &r;

object和其reference的大小相同,地址也相同(全都是假象)
Java里头所有变量都是reference

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
typedef struct Stag{int a, b, c, d;} S;
int main()
{
double x = 0;
double* p = &x;//p指向x,p的值是x的地址
double& r = x;//r代表x,现在r,x都是0

cout << sizeof(x) << endl;//8
cout << sizeof(p) << endl;//4
cout << sizeof(r) << endl;//8
cout << p << endl;//0065FDFC
cout << *p << endl;//0
cout << x << endl;//0
cout << r << endl;//0
cout << &x << endl;//0065FDFC
cout << &r << endl;//0065FDFC

S s;
S& rs = s;
cout << sizeof(s) << endl;//16
cout << sizeof(rs) << endl;//16
cout << &s << endl;//0065FDE8
cout << &rs << endl;//0065FDE8
}

object和其reference的大小相同,地址也相同(全都是假象)

reference的常见用途

1
2
3
4
5
6
7
8
void func1(Cls* pobj) {pobj->xxx();}
void func2(Cls obj) {obj.xxx();}////被调用端 写法相同,很好
void func3(Cls& obj) {obj.xxx();}//被调用端 写法相同,很好
......
Cls obj;
func1(&obj);//接口不同,困扰
fun2(obj);//调用端接口相同,很好
func3(obj);//调用端接口相同,很好

reference通常不用于声明变量,而用于参数类型(parameters type)和返回类型(return type)的描述。

以下被视为”same signature”(所以二者不能同时存在):

1
2
double imag(const double& im) {...}
double imag(const double im) {...} //Ambiguity

【注】imag(const double& im)为signature, 不含return type.
imag(const double& im)后面可以加const, const是函数签名的一部分。
所以imag(const double& im)和imag(const double& im) const两个函数可以并存。

对象模型(Object Model):关于vptr 和 vtbl

1
2
3
4
5
6
7
8
9
10
class A
{
public:
virtual void vfunc1();
virtual void vfunc2();
void func1();
void func2();
private:
int m_data1, m_data2;
};
1
2
3
4
5
6
7
8
class B:public A
{
public:
virtual void vfunc1();
void func2();
private:
int m_data3;
};
1
2
3
4
5
6
7
8
class C:public B
{
public:
virtual void vfunc1();
void func2();
private:
int m_data1 m_data4;
};

从内存上看

对象模型(Object Model):关于this

Template Method
关于this

再谈const

        const object(data members不得变动)  non-const object(data members可变动)
const member functions
(保证不更改data members)           √                √
non-const member functions
(不保证data members不变)           ×                √

当成员函数的const和non-const版本同时存在,const object只会(只能)调用const版本,non-const object只会(只能)调用non-const版本。

1
2
const String str("hello world");
str.print();

如果当初设计string::print()时未指明const,那么上行便是经由const object调用non-const member function,会出错。此非所愿。

non-const member functions可调用const member functions,反之则不行,会引发:

1
(VC)error C2662:cannot convert 'this' pointer from 'const class X' to 'class X &'.Conversion loses qualifiers

class template std::basic_string<…>有如下两个member functions:

1
2
3
4
5
6
7
charT
operator[](size_type pos) const
{....../*不必考虑COW*/}

reference
operator[](size_type pos)
{....../*必须考虑COW*/}

COW:Copy On Write

对象模型(Object Model):关于Dynamic Binding

静态绑定

动态绑定三个条件:

  1. 通过指针
  2. 虚函数
  3. 向上转型

动态绑定

再谈new和delete

::operator new, ::operator delete, ::operator new[], ::operator delete[]

new&delete

重载member operator new/delete

重载member operator new/delete

重载member operator new[]/delete[]

和上图的区别在于多了一个[]

1
2
3
4
5
6
class Foo
{
public:
void* operator new[](size_t);
void operator delete[](void*, size_t);
};

示例, 接口

示例

示例2
int 4字节,long 4字节,string(里面是个指针)4字节
有虚函数就多一个指针(12+4=16)

Foo[5] 数组,有5个,12*5=60,第一个记录有5个元素,这个记录的size为4,60+4=64
示例3

重载new(), delete()

我们可以重载class member operator new(),写出多个版本,前提是每一个版本的声明都必须有独特的参数列,其中第一参数必须是size_t,其余参数以new所指定的placement arguments为初值。出现于new(……)小括号内的便是所谓placement arguments。

1
Foo* pf = new(300, 'c') Foo;

我们也可以重载class member operator delete()(或称此为placement operator delete),写出多个版本,但它们绝不会被delete调用。只有当new所调用的ctor抛出exception,才会调用这些重载版的operator delete()。它只可能这样被调用,主要用来归还未能完全创建成功的object所占用的memory。

示例

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
class Foo
{
public:
Foo(){cout<<"Foo::Foo()" << endl; }
Foo(int){cout << "Foo::Foo(int)" << endl; throw Bad();}//class Bad{};
//故意在这儿抛出exception,测试placement operator delete.s

//(1)这里就是一般的operator new()的重载
void* operator new(size_t size)
{
return malloc(size);
}

//(2)这个就是标准库已提供的placement new()的重载(的形式),(所以此处也模拟standard placement new,就只是传回pointer)
void* operator new(size_t size, void* start)
{
return start;
}

//(3)这个才是崭新的palcement new
void* operator new(size_t size, long extra)
{
return malloc(size+extra);
}

//(4)这又是一个placement new
void* operator new(size_t size, long extra, char init)
{
return malloc(size+extra);
}

//(5)这又是一个placement new, 但故意写错第一参数的type(那必须是size_t以符合正常的operator new)
//void* operator new(long extra, char init)
//{
// [Error]'Operator new' takes type 'size_t'('unsigned int') as first parameter[-fpermissive]
// return malloc(extra);
//}

//以下是搭配上述placement new的各个所谓placement delete.
//当ctor发出异常,这儿对应的operator(placement) delete就会被调用.
//其用于是释放对应之placement new分配所得的memory.
//(1)这儿就是一般的operator delete()的重载
void operator delete(void*,size_t)
{cout << "operator delete(void*, size_t)" << endl;}

//(2)这是对应的(2)
void operator delete(void*,void*)
{cout << "operator delete(void*, void*)" << endl;}

//(3)这是对应的(3)
void operator delete(void*, long)
{cout << "operator delete(void*, long)" << endl;}

//(4)这是对应的(4)
void operator delete(void*, long, char)
{cout << "operator delete(void*, long, char)" << endl;}

private:
int m_i;
};

测试代码:

1
2
3
4
5
6
7
8
9
Foo start;
Foo* p1 = new Foo;
Foo* p2 = new(&start) Foo;
Foo* p3 = new(100) Foo;
Foo* p4 = new(100,'a') Foo;
Foo* p5 = new(100) Foo(1);//ctor抛出异常
Foo* p6 = new(100,'a') Foo(1);
Foo* p7 = new(&start) Foo(1);
Foo* p8 = new Foo(1);

test

ctor抛出异常,但G4.9没调用operator delete(void*, long),但G2.9确实调用了。

即使operator delete(…)未能一一对应于operator new(…),也不会出现任何报错。意思是:放弃处理ctor发出的异常。

basic_string使用new(extra)扩充申请量

basic_string使用new(extra)扩充申请量

评论